Statistics question

One can calculate the 95% confidence interval for the mean with the population standard deviation known. This will give us an upper and a lower confidence limit. What happens if we decide to calculate the 99% confidence interval? Describe how the increase in the confidence level has changed the width of the confidence interval. Do the same for the confidence interval set at 90%. Do an example and give real values for the intervals in your post.  The formula for a confidence interval is:x̄ +/- zα/2 ∙σ/ sqrt(n)     Use that formula with the numbers plugged into it. x̄ is the sample mean and n is the sample size (no. of samples collected). The population standard deviation is denoted by the greek letter sigma σ:(1-α)*100%  is the level of confidence.For example, in a 95% confidence interval 1- α =.95 Solving for α gives α =.05(Also, see Table 8.1 on page 359, under 95% confidence). Thus: α/2 = .05/2 =.025zα/2  denotes the z value on the bell-shaped curve whose right-tail area is α/2 .For example, on page 292 (under ‘what is this z value?’), the z value there is denoted by z.10 since the right-tail area of that z value is .10.If you are doing a 95% confidence interval for the mean using formula 8.1 on page 358, then zα/2 = z.025  = 1.96by looking up the z-value on table 8.1 on page 359 (under confidence level 95%). This means that the area to the right of z=1.96 is .025.

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